Practice Problems In Physics Abhay Kumar Pdf -

At $t = 2$ s, $a = 6(2) - 2 = 12 - 2 = 10$ m/s$^2$

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At maximum height, $v = 0$

Acceleration, $a = \frac{dv}{dt} = \frac{d}{dt}(3t^2 - 2t + 1)$ At $t = 2$ s, $a = 6(2)

(Please provide the actual requirement, I can help you) At $t = 2$ s